What is the specific heat capacity if it takes 1000 J of energy to heat 25 g of this substance by 100°C? Give your answer in J/kg°C.

4000J/kg°C

Explanation:

The quantity of Heat Energy (Q) required to heat substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 1000joules

M = 25grams (Convert grams to kilograms)

1000grams = 1kg

So, 25grams = (25/1000)kg

= 0.025kg

C = ? (Let unknown value be Z)

Φ = 100°C

Then, apply Q = MCΦ

1000j = 0.025kg x Z x 100°C

1000j = 2.5Kg°C x Z

Divide both sides by 2.5kg°C

1000j/2.5kg°C = (2.5Kg°C x Z)/2.5kg°C

4000J/kg°C = Z

Recall that Z is the specific heat capacity of the substance.

Thus, the specific heat capacity of the substance is 4000J/kg°C

400J/kg°C

Explanation:

E= m×c×(change in temperature)

E= 1000J

m= 25g= 0.025kg

Change in temperature = 100

1000= 0.025×c×100

1000=2.5c

c = 400J/kg°C

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temp rises, and expansion