Una pelota de béisbol sale despedida de un bate con una velocidad horizontal de 20 m/s. En un tiempo de 0.25 s, ¿a qué distancia habrá viajado horizontalmente y cuánto habrá caído verticalmente?

Translation:

A baseball is thrown from a bat with a horizontal speed of 20 m / s. In a time of 0.25 s, how far will you have traveled horizontally and how much will you have fallen vertically?

Explanation:

This question deals directly with projectile motions and we can use modifications of equation of motion since it's a horizontal motion.

(a). How far will it have travelled;

X = Vo * t

X = 20 * 2.5 = 50m

(b). How much will it have fallen vertically?

y = Voy + ½gt²

But Voy = 0

y = ½ * 9.8 * 2.5²

y = 30.625m

convex lenses are thicker at the middle. rays of light that pass through the lens are brought closer together (they converge). a convex lens is a converging lens. when parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2