Determine the direction of the force that will act on the charge in each of the following situations. A positive charge moving to the right in a magnetic field that points out of the screen. A positive charge moving to the right in an electric field that points out of the screen. A negative charge moving out of the screen in a magnetic field that points into the screen.

a) the force goes down, b) The electric force is out of the screen

c) the force is zero

Explanation:

To determine the direction of a magnetic force we use the right hand rule. For a positive charge, the thumb is in the direction of speed, the fingers extended in the direction of the magnetic field, and the palm points in the direction of force. Let's apply this to our case

a) thumb   to the right

 Fingers spread out

And the force goes down

b) the electric force in the direction of the electric field if the charge is positive

 Positive charge

Electric field out of the screen

The electric force is out of the screen

c) charge moving out screen

   Magnetic field entered on the screen

Since they are parallel, therefore the force is zero

are there options? cause you ain’t. real specific

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.