A 0.6Kg book slides on a horizontal table. The kinetic friction force on the book has magnitude 1.2N. How much work is done on the book by friction during a displacement of 2.9m to the left.

the answer is 3.1 his answer is wrong mines is right

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

answer///isobars;