How many electrons are contained on the negatively-charged side of a capacitor when it is fullycharged if it is connected to a 1.5 V battery, the capacitor’s square plates are 0.25 cm x 0.25 cm, and the plates’ separation is 1 mm?

A. 1.8 x 10^9
B. 3.8 x 10^8
C. 2.5 x 10^7
D. 5.2 x 10^5
E. 7.5 x 10^4

Explanation:

Capacitance of the capacitor

C = ε₀ A / d

(8.85 x 10⁻¹² x .25² x 10⁻⁴) / 1 x 10⁻³

C = .553125 x 10⁻¹³ F

Charge = capacitance x volt

= .553125 x 10⁻¹³ x 1.5

= .8296875 x 10⁻¹³ C

no of electrons

= charge / charge on one electron

= .8296875 10⁻¹³/ 1.6 x 10⁻¹⁹

= 5.2 x 10^5

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answer: electrons