A student fires a cannonball diagonally with an initial speed of 31m/s. Neglect drag and the initial height of the cannonball. What was the cannonball's total flight time

The cannons total flight time is 2.23seconds

Explanation:

A ball fired diagonally is fired at an angle of 45° to the horizontal. The motion of the fired ball is a projectile motion. A projectile is a motion in which an object fired into space with an initial velocity U is allowed to fall freely under the influence of gravitational force.

To total time of flight T of the cannon ball can be expressed as;

T = 2Usin(theta)/g where;

U is the initial velocity or speed of the ball = 31m/s

theta is the angle that the ball make with the horizontal = 45°

g is the acceleration due to gravity = 9.81m/s²

Substituting the given datas into the formula we have;

T = 31sin45°/9.81

T = 31×0.7071/9.81

T = 21.92/9.81

T = 2.23seconds

f is prop to m1xm2 double m1 double force

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s