The force of repulsion between to like charge table tennis balls is 8.2 X 10 ^-7 N if the charge on the two objects a 6.7 X10^-9 coulombs each what is the distance between the two charges?

0.702 m

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's Law:

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the objects

And the force is:

- Attractive if the two charges have opposite signs (+-)

- Repulsive if the two charges have same sign (++ or --)

In this problem we have:

is the force between the two balls

is the charge on each ball

Solving for r, we find the separation between the balls:

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

the maxium height is 34m/s