The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to have the same KE at the bottom as a 1520 kg car moving at 1.01 m/s (2.26 mph).

The angle from the vertical is 48.72°

Explanation:

Given :

Length of rope m

Mass of man Kg

Mass of car Kg

Velocity of car

According to conservation law,

Potential energy of man is converted to kinetic energy of car moving,

We calculate height,

                         ( ∵ )

    m

This is the distance of the rope at the bottom,

So we take difference of it.

⇒

We can calculate angle between them,

  48.72°

Therefore, the angle from the vertical is 48.72°

f=gm1m2/d^2 it d

f is force g is gravitaiton constant, m1 is mass of first object, m2 is mass of second object. d is distance between two object

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