A 1-m3 tank containing air at 25 °C and 500 kPa is connected through a valve to another tank containing 5 kg of air at 35 °C and 200 kPa. Now the valve is opened, and the entire system is allowed to reach thermal equilibrium with the surroundings, which are at 20 °C. Determine the volume of the second tank and the final equilibrium pressure of air.

Volume of the second tank is 3.21m³

Final eguilibrium presssure is 284.13kpa

Explanation:

Volume of the tank A,

Temperature of air in tank A,

Pressure of air in tank A, P_A = 500kPa

Mass of air in tank B, m_b = 5kg

Temperature of air in tank B,

Pressure of air in tank B,

Surrounding temperature,

Assuming, at given conditions air behaves as an ideal gas.

For air, gas constant R = 0.287 kJ/kmol K

From ideal gas equation, mass of air in tank A is determined by

Volume of the tank B can be determined from

so,when the valve is opened

Total volume,

Volume of the second tank is 3.21m³

Total mass of air,

The final equilibrium pressure (P) can be obtained from the ideal gas equation applied to total volume

Final eguilibrium presssure is 284.13kpa

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