The block compresses the spring a maximum distance of 13.00 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.260. What is the work done by the spring in bringing the block to rest

The question is not complete and the complete question is;

A moving 1.60 kg block collides with a horizontal spring whose spring constant is 262 N/m.

The block compresses the spring a maximum distance of 13.00 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.260. A)What is the work done by the spring in bringing the block to rest?

B)How much mechanical energy is being dissipated by the force of friction while the block is being brought to rest by the spring?

C)What is the speed of the block when it hits the spring?

A) Work done by spring = 1.31 J

Explanation:

We are given that;

Mass(m) = 1.6 kg

Spring Constant (k) = 262 N/m

Maximum distance of compression (x) = 13 cm = 0.13m

Coefficient of kinetic friction = 0.26

Now, from Hooke's law, the work done by the spring is given by;

W = (1/2)k•x²

Plugging in the relevant values, we obtain ;

W = (1/2) x 262 x 0.13² = 1.31 J

B) The energy dissipated by the force of friction which is the work done by the friction is given by the product of the friction force and the displacement of the block.

Thus, W_f = F_f•x

Where, F_f is frictional force which is given by, F_f = μmg

μ = coefficient of kinetic friction = 0.26

F_f = 0.26 x 1.6 x 9.81 = 4.08 N

Thus,

W_f = 4.08 x 0.13 = 0.53 J

C) Now, we can find the velocity by applying conservation of energy;

Thus,

(1/2)mv² = W + W_f

(1/2)mv² = 1.31 + 0.53

(1/2)mv² = 1.84

mv² = 1.84 x 2

v² = (1.84 x 2)/1.6 = 2.3

Thus,v = √2.3 = 1.52 m/s

i wanna say it’s between b and d, leaning more towards b.

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day