A machine part is initially rotating at 0.500 rad/s. Its rotation speeds up with constant angular acceleration 2.50 rad/s2. Through what angle has the machine part rotated when its angular speed equals 3.25 rad/s

The angle through which the machine part has rotated is 2.0625 rad

Explanation:

Given;

initial angular speed, ωi = 0.500 rad/s

angular acceleration, α = 2.50 rad/s².

Final  angular speed, ωf = 3.25 rad/s

Apply kinematic equation;

ωf² = ωi² + 2αθ

where;

θ is the angle through which the machine part has rotated

3.25² = 0.5² + (2 x 2.5)θ

10.5625 = 0.25 + 5θ

5θ = 10.5625 - 0.25

5θ = 10.3125

θ = 10.3125/5

θ = 2.0625 rad

Therefore, the angle through which the machine part has rotated is 2.0625 rad

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+15-35=-20

going in opposite directions