A 12.5 µF capacitor is connected to a power supply that maintains a constant potential difference of 24.0 V across the plates. A piece of material with a dielectric constant of 3.75 is placed between the plates, completely filling the space between them. How much energy is stored in the capacitor before and after the dielectric is inserted?

The energy stored before dielectric slab insert is J and after is J

Explanation:

Given :

Capacitance F

Potential difference V

Dielectric constant

The energy stored in the capacitor before dielectric slab inserted is,

  J

When dielectric slab placed the energy stored in capacitor increase by (k) times.

  J

Therefore, the energy stored before dielectric slab insert is J and after is J