For a bronze alloy, the stress at which plastic deformation begins is 267 MPa and the modulus of elasticity is 115 GPa. (a) What is the maximum load (in N) that may be applied to a specimen having a cross-sectional area of 206 mm2 without plastic deformation?

The maximum load that may be applied without plastic deformation should be less than 55,002 N.

Explanation:

The load that may be applied at which plastic deformation begins is obtained by multiplying the stress of the bronze alloy by its cross-sectional area.

Stress = 267 MPa = 267×10^6 = 2.67×10^8 Pa = 2.67×10^8 N/m^2

Cross-sectional area = 206 mm^2 = 206 mm^2 × (1 m/1000 mm)^2 = 2.06×10^-4 m^2

Load at which plastic deformation begins = 2.67×10^8 × 2.06×10^-4 = 55,002 N

Maximum load that may be applied without plastic deformation should be less than 55,002 N.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down