The wind is blowing horizontally at 30 m / s in a storm at P o , 20°C toward a wall, where it comes to a stop (stagnation) and leaves with negligible velocity similar to a diffuser with a very large exit area. Find the stagnation temperature from the energy equation.

 To=20.44 °C    

Explanation:

Given that

Velocity , v= 30 m/s

Temperature , T= 20°C

We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K

By using energy conservation ,the stagnation temperature is given as

Now by putting the values in the above equation we get

To= 293.44 K

To= 293.44 - 273 °C

To=20.44 °C

Therefore the stagnation temperature will be 20.44 °C.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

read more on -