Two particles that have the same mass m = 500 g are connected by a massless cord of � = 30 cm and rotate around O with angular speed ω = 2.0 rev/s. What is the angular momentum of the system?

The angular momentum of the system is 0.18kgm²/s

Explanation:

L = angular momentum of the particle 1 + angular momentum of the particle 2

L = ml²ω + ml²ω

L = 2ml²ω

Given that,

m = 500g are connected by a massless cord

   =0.500kg

l = 30cm

 = 0.30m

angular speed ω = 2.0 rev/s

angular momentum of the system =

L = 2ml²ω

L = 2 × 0.500 × (0.30)² × 2

L = 2 × 0.500 × 0.09 × 2

L = 0.18kgm²/s

Thus, the angular momentum of the system is 0.18kgm²/s

multiply 2kg by latent heat of vap