A loop of area 0.820 m2 is in a uniform magnetic field B = 0.646 T. The magnetic flux through the loop is 0.200 Wb. What is the angle between the the normal to the plane of the loop and the field? (Give the smallest positive angle.)

67.81°

Explanation:

Magnetic flux, Φ, is given as:

Φ = B*A*cosθ

Where B = magnetic field

A = area of loop

θ = angle

Therefore:

cosθ = Φ/(B*A)

cosθ = 0.2/(0.646 * 0.82)

cosθ = 0.3776

θ = 67.81°

d eras and periods

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it