Our lab partner wears a new pair of sneakers to lab and, rather than performing the required experiments, you decide to measure the coefficient of static friction they make with the lab floor. Your partner reports her mass to be 59.0 kg. Hooking up an industrial force sensor to your interface you give your partner a piece of rope attached to the sensor and begin to pull. When the sensor reads 318.3 N your partner starts to slip. Determine the coefficient of static friction between your partner and the floor.

The coefficient of static friction between your partner and the floor is 0.55

Explanation:

Given:

Mass Kg

Frictional force N

From the formula of frictional force,

Where coefficient of static friction,

Put the above values and find the coefficient of static friction.

Therefore, the coefficient of static friction between your partner and the floor is 0.55

answer: (431,2)

step-by-step explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂