Residential building codes typically require the use of 12 - gauge copper wire (diameter 0.205 cm) for wiring receptacles. Such circuits carry currents as large as 20.0 A. If a wire of smaller diameter (with a higher gauge number) carried that much current, the wire could rise to a high temperature and cause a fire. (a) Calculate the rate at which internal energy is produced in 1.00 m of 12 - gauge copper wire carrying 20.0 A. (b) Repeat the calculation for a 12 - gauge aluminum wire. (c) Explain whether a 12 - gauge aluminum wire would be as

a. 2.92*10^{-12}J/s

b. 4.82*10^{-12}J/s

Explanation:

You can use the expression for the rate of energy produce per unit time

where

rho: resistivity

I: current

l: length

you can also use that

resistivity cooper=18.35*10^{-19}ohm*m

resistivity aluminum=30.31*10^{-19}ohm*m

(a) cooper

(b) aluminum

(c) Aluminum produced more energy due to that its density and its resistivity are greater than for cooper

hope this helps!!

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y