The precession rate given by Equation 6 assumes that friction is negligible. If friction plays a role while the rotor is spinning (such that ω is constantly decreasing), will our observed precession rate be greater or less than what we would expect without friection? Why?

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explanation:

it's a b and

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm

answercollision;