One object has an excess of 74 electrons and another object has 50 less electrons than protons. If the two objects are separated by a distance of .35m, what is the electric force between the two? Is it attractive or repulsive?

, attractive

Explanation:

The charge of one electron is

And the first object has an excess of 74 electrons, , so the net charge of the first object is

The charge of one proton is

And the 2nd object has 50 less electrons than protons, , so the net charge of the 2nd object is

The electric force between two charged objects is given by Coulomb's law:

where

k is the Coulomb's constant

is the charge on the 1st object

is the charge on the 2nd object

r = 0.35 m is the distance between the two objects

Substituting, we find:

And the negative sign indicates that the force is attractive (in fact, the electric force between two charges of opposite sign is attractive, while the force between two charges of same sign is repulsive)

i think if it were me i whould divide 300 dide 15

step-by-step explanation: