A fish (8 kg) is being yanked vertically upward out of the water and the fishing line breaks. If the line is rated to a maximum tension of 160 N (~ 35 lb test), then what was the minimum acceleration of the fish (in m/s2)

Explanation:

Given:

Mass of the fish, 8 kg

Tension of the line, F = 160 N

Tension of the line, F + normal force = 0

Normal force, Fn = Mass × acceleration

Acceleration = force/mass

= 160/8

= 20 m/s^2

Minimum acceleration = 20 m/s^2

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