A thundercloud has an electric charge of 43.2 C near the top of the cloud and -38.7 C near the bottom of the cloud. The magnitude of the electric force between these two charges is 3.95 x 106 N. What is the average separation between these charges? (kc = 8.99 ×109 N • m2 / C2)

1950.65m

Explanation:

Coulomb's law states that the force F of attraction between two charges q1 and q2 is directly proportional to the product of the charges and inversely proportional to the square of the distance d between them. Mathematically;

|F| = k |q1||q2| /r²

Given |q1| = |43.2| C = 43.2C

|q2| = |-38.7|C = 38.7C

F = 3.95 x 106 N

d = ?

k is the coloumbs constant = 8.99 ×109 Nm2 / C2

Substituting this values in the formula to get distance d we have;

3.95x10^6= 8.99×10^9×43.2×38.7/d²

3.95x10^6d² = 15,029,841,600,000

d² =15,029,841,600,000/3,950,000

d² = 3,805,023.189

d = √3,805,023.189

d = 1950.65m

Average separation between the charges is 1950.65m

this is poiselle's equation from fluid mechanic in physics. mech eng

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it