A dog whistle is designed to produce a sound with a frequency beyond that which can be heard by humans (between 20,000 Hz and 27,000 Hz). If a particular whistle produces a sound with a frequency of 25,000 Hz, what is the sound’s speed? Assume the wavelength of this sound wave in air is 0.013m. *
4 points
325 m/s
250 m/s
113 m/s
467 m/s

The speed of the sound having a frequency of 25000 Hz and a wavelength of 0.013 m is 325 m/s

From the question given above, the following data were obtained:

Frequency = 25000 Hz

Wavelength = 0.013 m

Frequency = 25000 Hz

Wavelength = 0.013 m

Velocity = frequency × wavelength

Velocity = 25000 × 0.013

Therefore, the speed of the sound is 325 m/s

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325 m/s

Explanation:

The velocity of waves is given as the product of wavelength and frequency of the waves. This is expressed as s=fw where s is the speed, f is frequency and w is wavelength.

Sometimes, when provided with period, you get frequency as the reciprocal of period.

In this case, since the wavelength is given as 0.013 m and frequency as 25000 then we substitute them into the equation of speed as

S=25000*0.013=325 m/s

Therefore, the speed is 325 m/s

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