A proton traveling along the x-axis enters a region at x = 0 where the x-component of the electric field is given by E = Ao/x1/2. How much work is done on the proton by the electric field as it moves along the x-axis from x = 0 to x = 7 m?

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The value of the work done is .

Explanation:

When a charged particle having charge is moving through an electric field , the net force () on the charge is

and the work done () by the particle is

Given, .

Substitute the value of electric field in equation (1) and then substitute the result in equation (2).

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energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j