A solenoid with 500 turns has a radius of 0.040 m and is 40 cm long. If this solenoid carries a current of 12 A, what is the magnitude of the magnetic field near the center of the solenoid? (μ 0 = 4π × 10-7 T · m/A)

Explanation:

We are given that

Number of turns,N=500

Radius,r=0.04 m

Length of solenoid,L=40 cm=

1 m=100 cm

Current,I=12 A

We have to find the magnitude of magnetic field near the center of the solenoid.

Number of turns per unit length,n=

Magnetic field near the center of the solenoid,B=

Where

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

as technology advances, new experiments often expose problems in accepted theories. c

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-lavira: )