A 1.3 kgkg block slides along a frictionless surface at 1.3 m/sm/s . A second block, sliding at a faster 5.0 m/sm/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.5 m/sm/s . What was the mass of the second block?

0.624 kg

Explanation:

We are given that

Mass of one block,

We have to find the mass of second block.

Mass of second block,

Substitute the values

Hence, the mass of second block=0.624Kg

The mass of the second block is 0.624 kg.              

Explanation:

Given that,

Mass of the block 1, m₁ = 1.3 kg

Speed of block 1, u₁ = 1.3 m/s

Speed of block 2, u₂ = 5 m/s

The final velocity of the combined blocks is 2.5 m/s, V = 2.5 m/s

It is a case of inelastic collision. Using the conservation of linear momentum as :

So, the mass of the second block is 0.624 kg.              

answer: he got 23

explanation:

1/0.14nm = 10^10/1.4 a lot