A 3.6-volt battery is used to operate a cell phone for an hour. If the cell phone draws a current of 0.018 Amperes during that time, what is the energy lost by the battery?

233.28Joules

Explanation:

Energy lost by the battery is expressed as

Energy = Power × Time

Since Power user up = Current (I)×potential difference (V)

Energy lost = current × potential difference × time

Energy used up = IVt

Given the following parameters

I = 0.018Amperes, V = 3.6Volts t = 1hour = 1×60×60 = 3600seconds

Energy lost. = 0.018×3.6×3600

Energy lost by the battery = 233.28Joules

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