The motor exerts a force of F = (20t2) N on the cable, where t is in seconds. Determine the speed of the 25-kg crate when t = 4 s. The coefficients of static and kinetic friction between the crate and the plane are ms = 0.3 and mk = 0.25, respectively.

Explanation:

Force F = 20 t² N so force is variable.

friction on the crate = mgμ , μ is coefficient of kinetic  friction , m is mass

Net force

=  F - mgμ

= 20 t² - mgμ = m dv / dt  ( Newton's 2 nd law )

m dv = (20 t² - mgμ ) dt

Integrating on both sides,

m v  = 20 (t³ / 3) - mgμ t

Putting the values ,

25 x v = 20 x 4³/3 - 25 x 9.8 x .25 x 4

25 v = 426.67 - 245

25 v = 181.67

v = 7.27

v = 7.27  m /s

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

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