A charged particle with charge +7.5 nC moves to the right with a velocity of 25 m/s in a magnetic field of magnitude 7 mT which also points to the left. What is the magnitude of the force on the charged particle?

The magnitude of the force on the charged particle is 1.3125nN

Explanation:

Given;

magnitude of charge, q = +7.5 nC

velocity of the charged particle, v = 25 m/s

strength of magnetic field, B =  7 mT

Magnitude of force on charged particle in magnetic field is given as;

F = qvB

where;

F is the force on the moving particle

q is the charged particle

B is magnetic field strength

Substitute in the given values in the above equation, we will have;

F = 7.5 x 10⁻⁹ x 25 x 7 x 10⁻³

F = 1.3125 x 10⁻⁹ N

F = 1.3125nN

Therefore, the magnitude of the force on the charged particle is 1.3125nN

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​

answer///scientific method;