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Physics, 07.04.2020 18:53 kbraggs13

For a particle undergoing simple harmonic motion described by x(t) = (4.5 cm) cos ((3.4 Hz) t)x(t)=(4.5cm)cos((3.4Hz)t) Find the first two times that the particle crosses x(t) = 0.x(t)=0.

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For a particle undergoing simple harmonic motion described by x(t) = (4.5 cm) cos ((3.4 Hz) t)x...
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