A wire in a uniform magnetic field of 0.350 T carries a current of 3.50 A. If the magnitude of the magnetic force per unit length on the wire is 0.278 N/m, what is the angle between the magnetic field and the current?

13.12°

Explanation:

Parameters given:

Magnetic field strength, B = 0.350 T

Current in the wire, I = 3.5 A

Force per unit length, F/L = 0.278 N/m

The force on a wire due to the presence of a magnetic field is given as:

F = I*L*B*sinФ

where Ф = angle between the magnetic field and current

The force per unit length, F/L, will be:

F/L = I*B*sinФ

0.278 = 3.5 * 0.35 * sinФ

=> sinФ =

sinФ = 0.227

Ф =

Ф = 13.12°

The angle between the magnetic field and the current is 13.12°.

u can delete ur account.

1. go on google and write

2 open this and click on your profile pic and if your profile is not appearing, then u have to log in.

3. when u click on your profile pic, there appears four options on the top.

4. click on the 1st option and scroll down and go at the bottom.

5. click on edit profile.

6. there appears a option 'prefernces' and at that option at the right side , 'edit' is written.

7. click on the edit option.

8. there is a option " i want to delete my account" and click on that.

hope this u

and ur welcm

: )

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.