What is the acceleration of the car at segment C?

30 m/s2
–30 m/s2
40 m/s2
–40 m/s2

-30 m/s²

Explanation:

Given that,

Initial velocity at C (Vi) = 40 m/s

Final velocity at D Vf = 10 m/s

acceleration A = ?

Time taken T = Time at the end of segment C - Time at the start of segment C

(6s - 5s) = 1s

Recall that acceleration is the rate of change of velocity per unit time i.e acceleration = (Vf - Vi)/T

A = (10 m/s - 40 m/s) / 1s

A = -30 m/s / 1s

A = -30 m/s² (negative acceleration means the car slowed down at segment C)

Thus, the acceleration of the car at segment C is -30 m/s²

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2