A simple pendulum is 0.30 m long. At t = 0 it is released from rest starting at an angle of 17 ∘. Part A Ignoring friction, what will be the angular position of the pendulum at t = 0.35 s? Express your answer in degrees.

-7.072 °

Explanation:

According to the given data, angular position is defined by

angular position = 17 ° cos( wt)

Where,

w is the angular frequency

w = √(g/L)

where,

L= length and g = acceleration due to gravity  =>9.8m/s²

angle = 17 ° cos( √(g/L) t) >(note to solve your calculate should be in radian mode)

At t=0.35s  

angle = 17 ° x -0.416

angle= -7.072 °

Therefore,  the angular position of the pendulum at t = 0.35s is -7.072 °

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see earlier answer