Solenoid A has total number of turns N length L and diameter D. Solenoid B has total number of turns 2N, length 2L and diameter 2D. Inductance of solenoid A is

8 times inductance of solenoid B
1/4 of inductance of solenoid B
same as inductance of solenoid B
1/8 of inductance of solenoid B
four times of inductance of solenoid B

∴Inductance of solenoid A is of inductance of solenoid B.

Explanation:

Inductance of a solenoid is

N= number of turns

= length of the solenoid

d= diameter of the solenoid

A=cross section area

B=magnetic induction

= magnetic flux

= Current

Given that, Solenoid A has total number of turns N, length L and diameter D

The inductance of solenoid A is

Solenoid B has total number of turns 2N, length  2L and diameter 2D

The inductance of solenoid B is

Therefore,

∴Inductance of solenoid A is of inductance of solenoid B.

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