A gardener uses a water hose to fill a 30.0 L bucket. The gardener notes that it takes 1.00 min to fill the bucket. A nozzle with an opening of cross sectional area 0.500 cm2 is then attached to the hose. The nozzle is held so that water is projected horizontally from a point 1.00 m above the ground. Over what horizontal distance can the water be projected

The distance can the water be projected is 4.51 m

Explanation:

The speed of the water in the hose is equal to:

v1 = R/A1

If we solve the continuity for v2:

v2 = R/A2 (eq. 1)

The equation for the vertical position is:

yf = yi + vy*t - (1/2)gt²

yi = 0

vy = 0

Clearing t:

(eq. 2)

The equation for position is:

xf = xi + vxt = 0 + v2t = v2t (eq. 3)

Replacing equation 1 and 2 in equation 3:

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.