Two flat conductors are placed with their inner faces separated by 15 mm. If the surface charge density on inner face A is 48 pC/m2 and on inner face B is −48 pC/m 2 , calculate the electric potential difference ∆V = VA − VB. Use ǫ0 = 8.85419 × 10−12 C 2 /Nm2 . Answer in units of V.

(part 1 of 2) A proton is accelerated from rest through a potential difference of 25648 V. What is the kinetic energy of this proton after this acceleration? The mass of a proton is 1.673 × 10−27 kg and the elemental charge is 1.602 × 10−19 C. Answer in units of J.

(part 2 of 2) What is the speed of the proton after this acceleration? Answer in units of m/s.