An unstrained horizontal spring has a length of 0.44 m and a spring constant of 238 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.029 m relative to its unstrained length. Determine the possible algebraic signs and the magnitude of the charges.

Explanation:

Given that,

Length of the spring, l = 0.44 m

Spring constant of the spring, k = 238 N/m    

Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes.

Displacement in the spring, x = 0.029 m

The force acting on the spring is given by :

This force will act between charges as :

So, the magnitude of charge is and it has positive sign.

the skeletons of most mammals reach a certain size and then stop growing. however, many animals, including some mammals, keep growing throughout their lives. kangaroos, for example, just keep growing and growing until they die. also, the longer an animal lives the greater the chance it might catch some deadly disease.