A 80 mW laser beam is polarized horizontally. It then passes through two polarizers. The axis of the first polarizer is oriented at 30∘ from the horizontal, and that of the second is oriented at 60∘ from the horizontal.

The E(incident) for the first  polarizer is E(incident)=-76.1930384332

The E(incident) for the second  polarizer is E(incident)=12.340115991

Explanation:

Solving the problem:

Given

Transmitted data = 80 mW

First polarizer= 30 degree

Second polarizer= 60 degree

We have the formula,

E (transmitted) = E (incident)cos()

1. Through the first polarizer

E (transmitted) = E (incident)cos()

80=E(incident) cos(60 degree)     (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 60 degree

E(incident)=-76.1930384332

The E(incident) for the first  polarizer is E(incident)=-76.1930384332

2. Through the first polarizer

We have the formula,

E (transmitted) = E (incident)cos()

80=E(incident) cos(30 degree)     (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 30 degree

E(incident) =12.340115991

The E(incident) for the second  polarizer is E(incident)=12.340115991

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