The potential difference between the plates of an air-filled parallel-plate capacitor with a plate separation of 4 cm is 51 V. What is the magnitude of the electric field between the plates of this capacitor

Explanation:

Electric field between plates of a parallel plate capacitor is uniform .

In a uniform electric field , relation between electric field and potential gradient is as follows

electric field = potential gradient               [ E = - dV / dl ]

in the given case ,

dV = 51 V  ,

dl = 4 cm

=  4 x 10⁻² m

E = 51 /  4 x 10⁻²

= 12.75 x 10² V / m

= 1275 V / m

i think the answer is a, hope this : )

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

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c. 127 in.2

d. 1,018 in.2