Hey circuit includes three resistors in parallel, each with a resistance of 55 ohm's. If one of the devices breaks, what is the ratio of the final current to the original current?

The ratio of final current to the original current is 0.67

Explanation:

Given:

R₁ = 55 Ω

R₂ = 55 Ω

R₃ = 55 Ω

When the resistors are connected in parallel then the net resistance, R is:

According to ohm's law:

V = IR

where,

V is the voltage

I is the current

In this case, I =

                   I =

Case 2:

When one of the device breaks then two resistors are left. The net resistance is:

In this case, I =

Ratio of final current to original current =

The ratio of final current to the original current is 0.67

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