What is the current in the 60.0 Ω resistor?
A. 1.50 A
B. 80.0A
C. 12.0A
D. 2.00A

1.50 A

Explanation:

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2

R1 = 60Ω

R2 = 20Ω

Rtotal = 60Ω + 20Ω = 80Ω

Given that,

voltage of circuit (V) = 120.0 V

resistance of circuit (R) = 80Ω

current of circuit (I) = ?

Since, voltage, resistance and current are involved, apply the formula for ohms law to get current

Voltage = current x resistance

120.0V = I x 80Ω

I = 120.0V / 80Ω

I = 1.50 Amps

Since, the 60Ω and 20Ω resistors are connected in series, the same current of 1.50 Amps flows through both.

Thus, the current in the 60Ω is 1.50 Amps

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