A hollow spherical shell has mass 8.05kg and radius 0.215m . It is initially at rest and then rotates about a stationary axis that lies along a diameter with a constant acceleration of 0.895rad/s2 .

What is the kinetic energy of the shell after it has turned through 5.25rev ?

Express your answer with the appropriate units.

The kinetic energy of the shell after it has turned through 5.25rev is 7.32J

Explanation: Please see the attachments below

930.21J

Explanation:

The kinetic energy of a solid body that is rotating, is given  by:

where I is the moment of inertia and w is the angular velocity.

The moment of inertia for a spherical shell is:

where M is the mass and R is the radius of the sphere. By replacing we have

To calculate w we have to use the equation

where we have taken w0=0 rad/s.

Finally, by replacing I and w we obtain:

HOPE THIS HELPS!

where’s the list ? the question is incomplete

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .