The arm of a crane at a construction site is 17.0 m long, and it makes an angle of 11.6 ◦ with the horizontal. Assume that the maximum load the crane can handle is limited by the amount of torque the load produces around the base of the arm. What maximum torque can the crane withstand if the maximum load the crane can handle is 643 N? Answer in units of N · m.

τ_max ≈ 10,708 N.m

Explanation:

To find max torque, we need the component of force that is perpendicular to the direction of vector r.

Now, Torque is the perpendicular component of the force times the distance.

Thus;

τ_max = F x r

τ_max = (643 cos 11.6°) (17 )

τ_max ≈ 10,708 N.m

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