A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force) acts on her. The student has a mass of 73 kg, and the height of the water slide is 11.8 m. If the kinetic frictional force does -5.5 × 103 J of work, how fast is the student going at the bottom of the slide?

The velocity with which the student goes down the bottom of glide is 12.48m/s.

Explanation:

The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.

Given are

     mass of the student 73 kg

     height of water glide 11.8 m

     work done as -5.5*10³ J

Have to find speed at which the student goes down the glide.

According to Law of Conservation of energy,

          K.E =P.E+Work Done

 mv²/2=mgh +W

Rearranging the above eqn for v

v = √2(gh+W/m)

Substituting values,

V =  12.48 m/s.

The velocity with which the student goes down the bottom of glide is 12.48m/s.

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6