A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water. It takes a time of 2.90 s for the boat to travel from its highest point to its lowest, a total distance of 0.700 m . The fisherman sees that the wave crests are spaced a horizontal distance of 5.50 m apart.

wavelength   = 5.50 m

The period T = 5.80 s

The speed v = 0.948 m/s

Amplitude A of each wave  = 0.350 m

Explanation:

Since the wave crests is 5.50 m; then we can say that the distance from one peak to another is equal to a single wavelength;

SO; wavelength   = 5.50 m

Given that ; the time to travel from the highest point to the lowest point = 2.90 s

Thus ; which implies just only about half of one wavelength

The period  for one wavelength T = twice of half of one wavelength which can be expressed as :

T =

T = 2 (2.90 s)

T = 5.80 s

The speed of the wave can be determined via the formula;

The amplitude A is half the distance because the distance illustrates the peak to peak vertical displacement of the wave ;

∴

A =

A = 0.350 m

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

answer: electrons