Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 18 cm has a cord that has a pulling force of 50 N on it. What pulling force (in N) needs to be applied to the cord connecting the larger flywheel of radius 29 cm such that the combination does not rotate?

Explanation:

Given that,

Small wheel applied force

F₁ = 50N

Small wheel radius

r₁ = 18cm

Bigger wheel radius.

r₂ = 29cm

Bigger wheel applied force

F₂ =?

Since the combination of those forces did not cause the wheel to rotate,

Then, Στ = 0

F₁•r₁ —F₂•r₂ =

50×18 — 29F₂ = 0

900 = 29F₂

F₂ = 900 / 29

F₂ = 31.03 N

The pulling force applied at the larger wheel is 31.03N

correct it is c.) b b

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.