A disk with a rotational inertia of 2.0 kg·m2 and a radius of 0.40 m rotates on a frictionless fixed axis perpendicular to the disk faces and through its center. A force of 5.0 N is applied tangentially to the rim. The angular acceleration of the disk is?

To solve this problem we must apply the concepts related to the torque expressed as a function of the angular acceleration and the moment of inertia as well as the radius and the force. From these two definitions we will seek to find the angular acceleration of the body:

We know that Torque is defined as,

Here,

I = Moment of Inertia

= Angular acceleration

And at the same time, the torque is the product between the force and the radius, then we have

Here,

r = Radius

F = Force

Equation we have,

Rearranging to find the acceleration

Our values are,

Replacing this value at the previous equation

Therefore the angular acceleration of the disk is

explanation:

could i give you a exaplo that could you?

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.