A beam of light traveling in air strikes a slab of transparent material. The incident beam makes an angle of 40° with the normal, and the refracted beam make an angle of 26° with the normal. What is the speed of light in the transparent material?

V = 2.05× 10⁸ m/s

Explanation:

We are given;

The angle of the incidence; i = 40°

Angle of refraction; (r) = 26°

For us to find the speed of light in the material, we'll use Snell's law

From shell's law, we know that;

n = sin i/sin r = speed of light in air/Speed of light in the medium

Now, speed of light in air = 3 × 10⁸ m/s

Lets speed of light in medium be V

Thus, plugging in the relevant values to obtain;

Sin 40°/sin 26° = 3×10⁸/V

Let's make V the subject;

V = 3 × 10⁸× sin 26°/sin 40°

V = 2.05× 10⁸ m/s

explanation:

the masses of the objects and the distance between them

the body's situation won't change the forces are equal opposit and on the same body