Two objects are dropped from rest from the same height. Object A falls through a distance Da and during a time t, and object B falls through a distance Db during a time 2t. If air resistance is negligible, what is the relationship between Da and Db?
a. dA = ¼ dB.
b. dA = ½ dB.
c. dA = 2 dB.
d. dA = 4 dB.

a. Da = ¼ Db

Explanation:

Let us write out equations of motion for both objects:

For object A:

Since initial velocity, u =, is zero:

---------------------------------------- (1)

For object B:

Since initial velocity, u =, is zero:

---------------------------------------- (2)

Note: g = acceleration due to gravity

To get the relationship between Da and Db, we make g subject of formula in (1) and (2) and then equate:

From (1):

From (2):

Equating:

=>

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2