A particle with a charge of −1.7 μC and a mass of 3.0 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 43 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then give the answer as a negative number.

Explanation:

We are given that

Mass,m=

Speed,v=43 m/s

We have to find the potential difference between A and B.

By law of conservation of energy

Kinetic energy=Potential energy

Substitute the values

Negative charge is always accelerated towards  high potential.Therefore,potential at point B is higher than the potential at point A.

Hence,

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by